Difference between revisions of "Theoretical Aspects of Lexical Analysis/Exercise 4"

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<graph>
 
<graph>
 
digraph nfa {
 
digraph nfa {
     { node [shape=circle style=invis] start }
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     { node [shape=circle style=invis] s }
 
   rankdir=LR; ratio=0.5
 
   rankdir=LR; ratio=0.5
 
   node [shape=doublecircle,fixedsize=true,width=0.2,fontsize=10]; 17
 
   node [shape=doublecircle,fixedsize=true,width=0.2,fontsize=10]; 17
 
   node [shape=circle,fixedsize=true,width=0.2,fontsize=10];
 
   node [shape=circle,fixedsize=true,width=0.2,fontsize=10];
  
   start -> 0
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   0 -> 1  
 
   0 -> 1  
 
   1 -> 2  
 
   1 -> 2  
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<graph>
 
<graph>
 
digraph dfa {
 
digraph dfa {
     { node [shape=circle style=invis] start }
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     { node [shape=circle style=invis] s }
 
   rankdir=LR; ratio=0.5
 
   rankdir=LR; ratio=0.5
 
   node [shape=doublecircle,fixedsize=true,width=0.2,fontsize=10]; 4 5 6
 
   node [shape=doublecircle,fixedsize=true,width=0.2,fontsize=10]; 4 5 6
 
   node [shape=circle,fixedsize=true,width=0.2,fontsize=10];
 
   node [shape=circle,fixedsize=true,width=0.2,fontsize=10];
   start -> 0
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   s -> 0
   0 -> 1 [label="a"]
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   0 -> 1 [label="a",fontsize=10]
   0 -> 2 [label="b"]
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   0 -> 2 [label="b",fontsize=10]
   1 -> 1  [label="a"]
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   1 -> 1  [label="a",fontsize=10]
   1 -> 3  [label="b"]
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   1 -> 3  [label="b",fontsize=10]
   2 -> 1 [label="a"]
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   2 -> 1 [label="a",fontsize=10]
   2 -> 2 [label="b"]
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   2 -> 2 [label="b",fontsize=10]
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   3 -> 1 [label="a",fontsize=10]
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   6 -> 6 [label="b"]
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   fontsize=10
 
   fontsize=10
 
   //label="DFA for (a|b)*abb(a|b)*"
 
   //label="DFA for (a|b)*abb(a|b)*"
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<graph>
 
<graph>
 
digraph dfamin {
 
digraph dfamin {
     { node [shape=circle style=invis] start }
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     { node [shape=circle style=invis] s }
 
   rankdir=LR; ratio=0.5
 
   rankdir=LR; ratio=0.5
 
   node [shape=doublecircle,fixedsize=true,width=0.4,fontsize=10]; 456
 
   node [shape=doublecircle,fixedsize=true,width=0.4,fontsize=10]; 456
   node [shape=circle,fixedsize=true,width=0.2,fontsize=10];
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   node [shape=circle,fixedsize=true,width=0.3,fontsize=10];
   start -> 02
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   s -> 02
   02 -> 1 [label="a"]
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   02 -> 1 [label="a",fontsize=10]
   02 -> 02 [label="b"]
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   02 -> 02 [label="b",fontsize=10]
   1 -> 1  [label="a"]
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   1 -> 1  [label="a",fontsize=10]
   1 -> 3  [label="b"]
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   1 -> 3  [label="b",fontsize=10]
   3 -> 1 [label="a"]
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   3 -> 1 [label="a",fontsize=10]
   3 -> 456 [label="b"]
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   3 -> 456 [label="b",fontsize=10]
   456 -> 456 [label="a"]
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   456 -> 456 [label="a",fontsize=10]
   456 -> 456 [label="b"]
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   456 -> 456 [label="b",fontsize=10]
 
   fontsize=10
 
   fontsize=10
 
   //label="DFA for (a|b)*abb(a|b)*"
 
   //label="DFA for (a|b)*abb(a|b)*"

Revision as of 03:38, 22 March 2009

Use Thompson's algorithm to build the NFA for the following regular expression. Build the corresponding DFA and minimize it.

  • (a|b)*abb(a|b)*

Solution

NFA

The following is the result of applying Thompson's algorithm.


DFA

Determination table for the above NFA:

In α∈Σ move(In, α) ε-closure(move(In, α)) In+1 = ε-closure(move(In, α))
- - 0 0, 1, 2, 4, 7 0
0 a 3, 8 1, 2, 3, 4, 6, 7, 8 1
0 b 5 1, 2, 4, 5, 6, 7 2
1 a 3, 8 1, 2, 3, 4, 6, 7, 8 1
1 b 5, 9 1, 2, 4, 5, 6, 7, 9 3
2 a 3, 8 1, 2, 3, 4, 6, 7, 8 1
2 b 5 1, 2, 4, 5, 6, 7 2
3 a 3, 8 1, 2, 3, 4, 6, 7, 8 1
3 b 5, 10 1, 2, 4, 5, 6, 7, 10, 11, 12, 14, 17 4
4 a 3, 8, 13 1, 2, 3, 4, 6, 7, 8, 11, 12, 13, 14, 16, 17 5
4 b 5, 15 1, 2, 4, 5, 6, 7, 11, 12, 14, 15, 16, 17 6
5 a 3, 8, 13 1, 2, 3, 4, 6, 7, 8, 11, 12, 13, 14, 16, 17 5
5 b 5, 15 1, 2, 4, 5, 6, 7, 11, 12, 14, 15, 16, 17 6
6 a 3, 8, 13 1, 2, 3, 4, 6, 7, 8, 11, 12, 13, 14, 16, 17 5
6 b 5, 15 1, 2, 4, 5, 6, 7, 11, 12, 14, 15, 16, 17 6


Graphically, the DFA is represented as follows:


Given the minimization tree to the right, the final minimal DFA is:


The minimization tree is as follows. As can be seen, the states are indistinguishable.


The tree expansion for non-splitting sets has been omitted for simplicity ("a" transition for non-final states and the {0, 2} "a" and "b" transitions. The final states are all indistinguishable, regarding either "a" or "b" transitions.