Difference between revisions of "Theoretical Aspects of Lexical Analysis/Exercise 5"

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(NFA)
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== NFA ==
 
 
The following is the result of applying Thompson's algorithm. State '''3''' recognizes the first expression (token '''T1'''); state '''8''' recognizes token '''T2'''; and state '''14''' recognizes token '''T3'''.
 
 
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== NFA ==
 
== NFA ==

Revision as of 18:59, 27 January 2015

Compute the non-deterministic finite automaton (NFA) by using Thompson's algorithm. Compute the minimal deterministic finite automaton (DFA).
The alphabet is Σ = { a, b }. Indicate the number of processing steps for the given input string.

  • G = { ab, ab*, a|b }, input string = abaabb

NFA

The following is the result of applying Thompson's algorithm. State 3 recognizes the first expression (token T1); state 8 recognizes token T2; and state 14 recognizes token T3.


NFA

The following is the result of applying Thompson's algorithm. State 3 recognizes the first expression (token T1); state 8 recognizes token T2; and state 14 recognizes token T3.

DFA

Determination table for the above NFA:

In α∈Σ move(In, α) ε-closure(move(In, α)) In+1 = ε-closure(move(In, α))
- - 0 0, 1, 4, 9, 10, 12 0
0 a 2, 5, 11 2, 5, 6, 8, 11, 14 1 (T2)
0 b 13 13, 14 2 (T3)
1 a - - -
1 b 3, 7 3, 6, 7, 8 3 (T1)
2 a - - -
2 b - - -
3 a - - -
3 b 7 6, 7, 8 4 (T2)
4 a - - -
4 b 7 6, 7, 8 4 (T2)

Graphically, the DFA is represented as follows:


The minimization tree is as follows. Note that before considering transition behavior, states are split according to the token they recognize.


The tree expansion for non-splitting sets has been omitted for simplicity ("a" transition for final states {1, 4}).

Given the minimization tree, the final minimal DFA is exactly the same as the original DFA (all leaf sets are singular).

Input Analysis

In Input In+1 / Token
0 abaabb$ 1
1 baabb$ 3
3 aabb$ T1
0 aabb$ 1
1 abb$ T2
0 abb$ 1
1 bb$ 3
3 b$ 4
4 $ T2

The input string abaabb is, after 9 steps, split into three tokens: T1 (corresponding to lexeme ab), T2 (a), and T2 (abb).