Theoretical Aspects of Lexical Analysis/Exercise 2

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Problem

Use Thompson's algorithm to build the NFA for the following regular expression. Build the corresponding DFA and minimize it.

  • (a*|b*)*

Solution

The non-deterministic finite automaton (NFA), built by applying Thompson's algorithm to the regular expression (a*|b*)* is the following:

nfa 0 0 start->0 11 11 0->11 1 1 0->1 2 2 1->2 6 6 1->6 3 3 2->3 5 5 2->5 7 7 6->7 9 9 6->9 4 4 3->4 a 10 10 5->10 4->3 4->5 10->11 10->1 8 8 7->8 b 9->10 8->7 8->9

Applying the determination algorithm to the above NFA, the following determination table is obtained:

In α∈Σ move(In, α) ε-closure(move(In, α)) In+1 = ε-closure(move(In, α))
- - 0 0, 1, 2, 3, 5, 6, 7, 9, 10, 11 0
0 a 4 1, 2, 3, 4, 5, 6, 7, 9, 10, 11 1
0 b 8 1, 2, 3, 5, 6, 7, 8, 9, 10, 11 2
1 a 4 1, 2, 3, 4, 5, 6, 7, 9, 10, 11 1
1 b 8 1, 2, 3, 5, 6, 7, 8, 9, 10, 11 2
2 a 4 1, 2, 3, 4, 5, 6, 7, 9, 10, 11 1
2 b 8 1, 2, 3, 5, 6, 7, 8, 9, 10, 11 2
Graphically, the DFA is represented as follows:
dfa 0 0 start->0 1 1 0->1 a 2 2 0->2 b 1->1 a 1->2 b 2->1 a 2->2 b

Given the minimization tree to the right, the final minimal DFA is:

dfamin 012 012 start->012 012->012 a 012->012 b
The minimization tree is as follows. As can be seen, the states are indistinguishable.
mintree {0, 1, 2} {0, 1, 2} {} {} {0, 1, 2}->{} NF {0, 1, 2} {0, 1, 2} {0, 1, 2}->{0, 1, 2}  F {0, 1, 2} {0, 1, 2} {0, 1, 2}->{0, 1, 2}  a,b