Case in which it is: f(± a) = 0
| μ = 0 σ = a ⁄ √ 6 = 0.4082… a | |||
| x is in [−a, 0] | f1 = (1 + x/a) / a | F1 = ½ (1 + x/a)² | x = − a [1 − √(2 F1)] |
| x is in [0, a] | f2 = (1 − x/a) / a | F2 = 1 − ½ (1 − x/a)² | x = a {1 − √[2 (1 − F2)]} |
| ◊ | Created: 2001-01 — Last update: 2004-10-13 |